Formula from Chapter 2: protons and electrons have opposite charges

\(N_{\mathrm{charge}} = N_{\mathrm{\ce{p+}}} - N_{\mathrm{\ce{e-}}}\)

\(N_{\mathrm{\ce{p+}}}\) \(= 8\) e.g. oxygen atom has atomic number of 8, i.e. 8 protons

\(N_{\mathrm{\ce{n^0}}}\) \(= 10\) there is an ion with a total of 10 electrons (2 inner and 8 valence)

N_charge = N[p+] - N[e-] # charge of this ion is negative two

unknown symbol |N[e-]| encountered (check spelling and capitalization)