Formula from Chapter 4: Calculating percent yield from masses

\(\mathrm{yield}_{\mathrm{rel}} = \dfrac{m_{\mathrm{actual}}}{m_{\mathrm{theoretical}}} \cdot 100\ \mathrm{%}\)     

\(m_{\mathrm{\ce{H2O},theoretical}}\) \(= 19.57\ \mathrm{g}\)


\(m_{\mathrm{\ce{H2O},actual}}\) \(= 18.35\ \mathrm{g}\)


\(\mathrm{yield}_{\mathrm{rel}}\) \(= \dfrac{m_{\mathrm{\ce{H2O},actual}}}{m_{\mathrm{\ce{H2O},theoretical}}} \cdot 100\ \mathrm{%}\)

\(\ \ \ =\dfrac{18.35\ \mathrm{g}}{19.57\ \mathrm{g}} \cdot 100\ \mathrm{%}\)

\(\ \ \ =0.93766 \cdot 100\ \mathrm{%}\)

\(\ \ \ =93.77\ \mathrm{%}\)