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Formula from Chapter 4: Calculating percent yield from masses
\(\mathrm{yield}_{\mathrm{rel}} = \dfrac{m_{\mathrm{actual}}}{m_{\mathrm{theoretical}}} \cdot 100\ \mathrm{％}\)
\(m_{\mathrm{\ce{H2O},theoretical}}\)
\(= 19.57\ \mathrm{g}\)
\(m_{\mathrm{\ce{H2O},actual}}\)
\(= 18.35\ \mathrm{g}\)
\(\mathrm{yield}_{\mathrm{rel}}\)
\(= \dfrac{m_{\mathrm{\ce{H2O},actual}}}{m_{\mathrm{\ce{H2O},theoretical}}} \cdot 100\ \mathrm{％}\)
\(\ \ \ =\dfrac{18.35\ \mathrm{g}}{19.57\ \mathrm{g}} \cdot 100\ \mathrm{％}\)
\(\ \ \ =0.93766 \cdot 100\ \mathrm{％}\)
\(\ \ \ =93.77\ \mathrm{％}\)