Example 7.1: Determining the Electronic Structures of Cations

There are at least 14 elements categorized as “essential trace elements” for the human body. They are called “essential” because they are required for healthy bodily functions, “trace” because they are required only in small amounts, and “elements” in spite of the fact that they are really ions. Two of these essential trace elements, chromium and zinc, are required as \(\ce{Cr^3+}\) and \(\ce{Zn^2+}\). Write the electron configurations of these cations.

Solution

First, write the electron configuration for the neutral atoms:

\(\ce{Zn: [Ar] 3d^10 4s^2}\)

\(\ce{Cr: [Ar] 3d^5 4s^1}\)

Next, remove electrons from the highest energy orbital. For the transition metals, electrons are removed from the s orbital first and then from the d orbital. For the p-block elements, electrons are removed from the p orbitals and then from the s orbital. Zinc is a member of group 12, so it should have a charge of \(\ce{2+}\), and thus loses only the two electrons in its s orbital. Chromium is a transition element and should lose its s electrons and then its d electrons when forming a cation. Thus, we find the following electron configurations of the ions:

\(\ce{Zn^2+: [Ar] 3d^10}\)

\(\ce{Cr^3+: [Ar] 3d^3}\)