Example 4.13b: Calculation of Percent Yield

What is the percent yield of a reaction that produces 12.5 g of the gas Freon \(\ce{CF2Cl2}\) from 32.9 g of \(\ce{CCl4}\) and excess \(\ce{HF}\)?

\(\ce{CCl4}\)\(\ce{ + }\)\(\ce{2HF}\)\(\ce{->}\)\(\ce{CF2Cl2}\)\(\ce{ + }\)\(\ce{2HCl}\)\(\ce{ }\)


Think about it...